Tuesday, June 22, 2010

I.1. it is part (d), since the vertaical asymptote is x=2 and the horizontal asymptote is y=1.
2.a) x belongs ]-infinity,2[ union ]2, infinity[
b) easy
3. a) x is impossible
b) x is less than 2 or x is greater than 3
c) x is less than or equal to 1 or x is greater than or equal to 2.5

4. y is less than 0 or y is greater than 1.25

III. b) (EA) and (FG) are skew.

c) (CN) is a subset of (ABCD)

(AD)= the intersection between (ABCD) and (ADH).

So, (CN) intersection (ADH) is equal to (CN) intersection (AD)

d) (ADH) is the same as (ADHE)

M belongs to planes (MNE) and (ADHE)

E belongs to planes (MNE) and (ADHE)

So, (ME) is the intersection of (MNE) and (ADH)

e) By Thales' theorem (MN) is parallel to (BD)

f) (MN) is parallel to (BD) which is parallel to (FH)

So, (MN) is parallel to (HEF)

g) a line passing through E parallel to (MN) and (FH)

http://www.scribd.com/doc/33421365/Final-Exercise-2

I. 1) x belongs to [0,10]
2) (JK) is parallel to (BC), therefore, angle AJM is equal to angle ABC (corresponding angles) and similarly angle AKM is equal to angle ACB. Since triangle ABC is isosceles, then angle ABC is equal to angle ACB, and thus angle AJM is equal to AKM. So triangle AJK is isosceles and [AM] height, therefore M midpoint of [JK]. So JM=MK.
3) (AM)/(AH)= (JM)/(BH)
(x)/(10)= (JM)/(6)
JM= (6x)/10
f(x)= JK*MH=2*JM*MH=2*(6x/10)*(10-x)=12x-6(x^2)/5
4) just develop it.
5) nothing new
6) max at (5,30)